Question 3 (a) For each pair of molecules, determine their...

Question 3 (a) For each pair of molecules, determine their relationship: INSTRUCTIONS: Choose 1 letter from options A through E below and submit it on the MS Form Formatting may be lost in the question above - see the slide shown in class for correct formatting A. The same molecule drawn differently B. Enantiomers C. Geometric Isomers D. Constitutional Isomers E. Not related as isomers Question 3 (b) For each pair of molecules, determine their relationship: INSTRUCTIONS: Choose 1 letter from options A through E below and submit it on the MS Form Formatting may be lost in the question above - see the slide shown in class for correct formatting A. The same molecule drawn differently B. Enantiomers C. Geometric Isomers D. Constitutional Isomers E. Not related as isomers

Transcript

00:01 Hello students, in this question we have to tell the correct isomeric relationships between the given molecules.

00:07 Let's look at the first example.

00:10 In the first example we have two cyclohexane chair forms which contain the first chair form contains two methyl group at one two carbons.

00:21 However the second chair form contains methyl groups at one and three carbons.

00:29 So we can see that the atoms to which these different methyl groups are bonding are different.

00:36 So they will be referred as constitutional isomers.

00:45 Now let's look at second example.

00:49 Our second example contains this molecule given in the newman's form.

00:55 So let's first convert it into a wedge dash projection.

00:59 Consider that this molecule is rotated through an axis going through this front carbon like this.

01:07 Hence we will get a molecule which will contain hydroxyl group here.

01:12 Ch3 will go below the plane and this hydrogen will come above the plane and here we will have a ch2 group or we can simply draw it like this.

01:26 Now let's rotate this sigma bond to bring this methyl group on the left side.

01:35 Therefore this molecule will become oh group here.

01:39 This ch2et group will be on the left side and this methyl group will come above the plane and hydrogen will go behind the plane.

01:54 Similarly is the second molecule also contain a hydrogen atom behind the plane.

01:59 Now these are our two molecules.

02:02 We can see that they are mirror images of each other.

02:07 However they are not superimposable.

02:10 They will be our enantiomers.

02:17 Now let's look at the third example.

02:21 In the third example, we have given this cyclohexane and chair form of another molecule of cyclohexane.

02:28 So let's first convert this wedge dash projection into a chair form as well...

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