00:01
Hello students, in this question we have a horizontal spring.
00:05
So, horizontal spring is there.
00:08
So, it has a spring constant k is equal to 40 newton per meter and it undergoes a simple harmonic motion with the mass.
00:17
So, mass m is equal to 1 .2 kilogram and it stretches a distance which is equal to 20 centimeter.
00:29
Now, we need to calculate the speed of this at distance d2 is equal to 5 centimeter is equal to 0 .2 meter this is equal to 0 .05 meter.
00:42
So, since this is a horizontal displacement there is no gravitational force here.
00:47
So, you can ignore everything including gravity.
00:50
So, we only have the potential energy here.
00:54
So, its potential energy is given by the equation half k x square where x is the displacement, k is the spring constant.
01:04
Now, the change in potential energy at 20 centimeter and then at 5 centimeter when it transcribes it will have a change in potential energy delta pe.
01:18
So, that will be equal to half k can be taken outside displacement is 220 square.
01:25
So, that is 0 .2 square minus 0 .05 square...