QUESTION 3 Calculate the magnitude of $V_L$ in the following circuit, when frequency is 50 Hz and the value for the voltage and impedances are the following: $V_1 = 3$ Volts $R = 36$ Ohms $C = 0.000139$ Farads $L = 0.06$ Henrys $+ V_L -$ $X_L$ $L$ $I$ $+$ $V_1 \angle 0^\circ$ $R$ $X_C$ $C$ The polar representation of $V_L$ has two components: magnitude and angle. We are interested in the magnitude only. Use 3 decimals in your calculations and 2 in your answer. Do not include units in your answer.
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The angular frequency is $\omega = 2\pi f = 2\pi(50) = 100\pi \approx 314.159 \, rad/s$. $X_L = \omega L = 314.159 \times 0.06 = 18.849 \, \Omega$ $X_C = \frac{1}{\omega C} = \frac{1}{314.159 \times 0.000139} \approx 22.836 \, \Omega$ Show more…
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