00:01
Hello students welcome here in this question we have a reaction so ch3 ch2 c double 1 o h is given so it is reacting with h cn so this one is reaction 1 and ch3 ch2 o h and h is h is producing so it is a reaction mechanism 2 it is ch3, ch2, cohh, coh is producing.
00:38
So now these compounds are given.
00:43
This one is p compound, this one is q and this one is r.
00:48
So the first question is, what is the reaction mechanism one? so ch3, ch2, c1o, h is reacting with hcn.
01:00
So this is hcn minus and h plus.
01:04
So this one go and get attached here and this will relocate.
01:09
So, h3, ch2, c, cn, and here it is oh, it is h.
01:17
So this is attack.
01:20
So the reaction mechanism is nuclear.
01:24
Photophilic addition mechanism.
01:30
So the second question they are asking, there are two questions in this one.
01:34
So the first question is, what is the name of this compound? so we can see 1, 2, 3, 4.
01:41
So second position there is a hydroxy group, hydroxy, and butane this one is, butane and nitrile.
01:52
Nitrile group is the function.
01:54
Group here and the next one is here the they are asking the second question the isomer of q so c4 the formula is given for this one c4 h7 no is given so it isomer of q compound so c h 3 how many 7 will be there so c c c c c it is and this one is a nitral this is a q compound which is acyl nitrile acid compound is given acyl chloride compound which is formed from this one is formed from acyl chloride reacting with nh3 so here acyl chloride means it is c11 .0 cl so here it is 7 carbon should be there so 7 means this one is when h -3 is reacting, here it will be ch3, c -c -c -c -w -o -n -h.
03:05
So the reaction is this one.
03:07
So we want another, there is two carbons are present.
03:11
So four, five are there.
03:13
So here there is one and this is one.
03:15
So total, this is a compound which is the isomer of q compound.
03:20
So the trans compound we have to rise, cis and trans compounds for this one.
03:25
H double bond ch so here it is c double bond o n h2 and here it is so if you take this one at this is trans we want to write so here it is h and h and c h 3 so this is a cis compound and here it is c h i'm sorry there is no h and here also there is no h so we just want to write cis and trans compounds for this one...