Question 3 How large of a sample is needed in order to have a margin of error of 4% when n = 368, x = 116, and ? = 0.01? Note: Round your answer to a whole number.
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We can do this by using the formula: σ = √(p * (1 - p) / n) where p is the proportion of successes (X/n) and n is the sample size. In this case, X = 116 and n = 368, so the proportion of successes (p) is: p = X / n = 116 / 368 ≈ 0.3152 Now we can find the Show more…
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