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Hi.
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Here in this given problem there are three different questions.
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First of all in question number three.
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The situation is not practically but as per the given condition there is a bar magnet whose north pole is set to be towards left.
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This is the north, this is south and we know the direction of magnetic field around a bar magnet it comes out of the north pole then it bends like this and enters into the south pole then there is an electron beam which is supposed to be moving towards us so as it is moving towards us so we can assume it to be moving perpendicular to the plane of screen coming out this is the electron beam and then we have to find the deflection taking place in this electron beam.
01:04
So using an expression for the magnetic lawrence force, magnetic lawrence force, the force experienced by a charge particle moving in a magnetic field.
01:20
So using expression for the magnetic lawrence force f is equal to minus e, the charge carried by an electron into v cross b.
01:46
Here b is towards right magnetic field vector, velocity vector out of the screen.
01:55
So using right hand screw rule in this v cross b, its direction is that is up upward in the plane of paper.
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So f because of this negative sign of the electron that will be downward.
02:38
So the electron beam will be deflected down.
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Answer for this question number three.
02:47
Then question number four.
02:53
In this question there is a magnet which is stationary in the coil so when the magnet is stationary in the coil flux linked through it will also be constant magnetic flux linked through the coil will be constant it will not be changing so there will be no induced current...