Question

The average number of times Americans dine out in a week fell from 4.0 in 2008 to 3.8 in 2012 (Zagat.com, April 1, 2012). The number of times a sample of 20 families dined out last week provides the following data: 6 1 5 3 7 3 0 3 1 3 4 1 2 4 1 0 5 6 3 1 [4 pts] Compute the 20th and 35th percentiles.

Name: question 3 the average number of times americans dine out in a week fell from 40 in 2008 to 38 in 2012 zagatcom april 12012 the number of times a sample of 20 families dined out last week pr 46259
Uploaded: 2021-10-23T06:34:48-08:00
Duration: 2 min 39 s
Channel: Manisha Sarker
Description: question 3 the average number of times americans dine out in a week fell from 40 in 2008 to 38 in 2012 zagatcom april 12012 the number of times a sample of 20 families dined out last week pr 46259

          The average number of times Americans dine out in a week fell from 4.0 in 2008 to 3.8 in 2012 (Zagat.com, April 1, 2012). The number of times a sample of 20 families dined out last week provides the following data:
6 1 5 3 7 3 0 3 1 3
4 1 2 4 1 0 5 6 3 1

[4 pts] Compute the 20th and 35th percentiles.

Added by Laurie P.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Manisha Sarker

10/23/2021

Step 1

Step 1:** Arrange the given data in ascending order: 0 0 1 1 1 1 1 2 3 3 3 3 4 4 5 5 6 6 7 ** Show more…

Show all steps

Thanks for your feedback!

The average number of times Americans dine out in a week fell from 4.0 in 2008 to 3.8 in 2012 (Zagat.com, April 1, 2012). The number of times a sample of 20 families dined out last week provides the following data: 6 1 5 3 7 3 0 3 1 3 4 1 2 4 1 0 5 6 3 1 [4 pts] Compute the 20th and 35th percentiles.