00:01
In the first question of this problem, we are given three vectors.
00:05
Vector a is the vector 3 -00.
00:08
Vector b is the vector 508.
00:11
And vector c is the vector 0 -20 -0.
00:17
The first question is to determine the magnitude of the vector, that is, the sum of these three vectors.
00:26
So the sum of the vectors a, b, and c is the sum of 3 -0.
00:32
5 .08 and 0200.
00:38
Now the sum of three vectors is obtained as a vector with the components, the sum of the corresponding components of the vector being added.
00:47
So it is the vector with components 3 plus 5 plus 0 plus 20 and 0 plus 8 plus 0.
00:55
That is it is the vector 8 28.
01:02
Of this vector a plus b plus c is obtained as square root of 8 square plus 20 square plus 8 square which is square root of 64 plus 400 plus 64 that is square root of 528 that can be approximated as 22 .98 by rounding to 2 decimal places and this is the required answer in the next problem, we are asked to determine the horizontal component of a force of magnitude 330 newton that is acting at an angle of 75 degree counterclockwise measured from the negative vertical axis.
01:50
So here if fx denotes the horizontal component of the force vector ff, then, then the horizontal component is the magnitude of the force times cos theta where theta is the angle measured from the positive x axis in the counter loquoise direction.
02:17
Consider the coordinate axis.
02:19
This is a positive x axis...