Question \( 310 \mathrm{pts} \) A 200-g metal container; insulated on the outside; holds \( 100 \mathrm{~g} \) of water in thermal equ. at 22.00*+. A 21 -g ice cube; at the melting point; is dropped into the water; and when thermal equilibrium reached the temperature is 15.00 " \( € \) Assume there is no heat exchange with the surroundings For water; \( t \) specific heat is \( 4190 \mathrm{~J} / \mathrm{kg} \) Kand the heat of fusion is \( 3.34105 \mathrm{Jkg} \). The specific heat for the metal is close: \( 5450 \mathrm{~J} / \mathrm{kg} 4450 \mathrm{~J} / \mathrm{kg} 3850 \mathrm{~J} / \mathrm{kg} 2730 \mathrm{Jkg} 4950 \mathrm{M} / \mathrm{kg} \cdot \mathrm{K} \)
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