Question 35 1 pts The dimensional equivalent of the quantity impulse in terms of the fundamental quantities (mass, length, time) is which of the following? $MLT^{-1}$ $ML^2T^{-2}$ $MLT$ $MLT^{-2}$
Added by Kimberly M.
Close
Step 1
Impulse = Force x Time Force = Mass x Acceleration Acceleration = Length / Time$^2$ Show more…
Show all steps
Your feedback will help us improve your experience
Mirza Aslam Beig and 94 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Dimensions of impulse are. (a) $\mathrm{M}^{-1} \mathrm{~L}^{-1} \mathrm{~T}^{1}$ (b) $\mathrm{M}^{1} \mathrm{~L}^{1} \mathrm{~T}^{-1}$ (c) $\mathrm{M}^{1} \mathrm{~L}^{1} \mathrm{~T}^{1}$ (d) $\mathrm{M}^{1} \mathrm{~L}^{2} \mathrm{~T}^{-2}$
The dimensional formula of the ratio of angular to linear momentum is (a) $\left[\mathrm{M}^{0} \mathrm{LT}^{0}\right]$ (b) [MLT] (c) $\left[\mathrm{ML}^{2} \mathrm{~T}^{-1}\right]$ (d) $\left[\mathrm{M}^{-1} \mathrm{~L}^{-1} \mathrm{~T}^{-1}\right]$
Units and Measurements
Round 1
Dimensions of resistance in an electrical circuit, in terms of dimension of mass $M$, of length $L$, of time $T$ and of current $I$, would be $\quad$ [UP SEE 2007] (a) $\left[\mathrm{ML}^{2} \mathrm{~T}^{-3} \mathrm{I}^{-1}\right]$ (b) $\left[\mathrm{ML}^{2} \mathrm{~T}^{-2}\right]$ [c) $\left[\mathrm{ML}^{2} \mathrm{~T}^{-1} \mathrm{l}^{-1}\right]$ (d) $\left[\mathrm{ML}^{2} \mathrm{~T}-3 \mathrm{I}^{-2}\right]$
Round 2
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD