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QUESTION 3. The air is compressed adiabatically from 1 bar and 300 K properties to 15 bar and specific volume 0.12 m³/kg properties in a closed system. The air is then cooled to 300 K at a constant volume. By accepting the perfect gas, ignoring the kinetic and potential energy changes; a) Show the processes in the P-v diagram. b) Calculate the work for the 1st Process and the heat for the 2nd Process using the tables for unit kg of air. c) Calculate the work for the 1st Process and the heat for the 2nd Process per unit kg of air using the specific heat at 300 K. 

          QUESTION 3. The air is compressed adiabatically from 1 bar and 300 K properties to 15 bar and specific volume 0.12 m³/kg properties in a closed system. The air is then cooled to 300 K at a constant volume. By accepting the perfect gas, ignoring the kinetic and potential energy changes; a) Show the processes in the P-v diagram. b) Calculate the work for the 1st Process and the heat for the 2nd Process using the tables for unit kg of air. c) Calculate the work for the 1st Process and the heat for the 2nd Process per unit kg of air using the specific heat at 300 K.
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QUESTION 3. The air is compressed adiabatically from 1 bar and 300 K properties to 15 bar and specific volume 0.12 m³/kg properties in a closed system. The air is then cooled to 300 K at a constant volume. By accepting the perfect gas, ignoring the kinetic and potential energy changes; a) Show the processes in the P-v diagram. b) Calculate the work for the 1st Process and the heat for the 2nd Process using the tables for unit kg of air. c) Calculate the work for the 1st Process and the heat for the 2nd Process per unit kg of air using the specific heat at 300 K.

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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QUESTION 3. The air is compressed adiabatically from 1 bar and 300 K properties to 15 bar and specific volume 0.12 m3/kg properties in a closed system. The air is then cooled to 300 K. a) Show the processes in the P-v diagram. b) Calculate the work for the 1st Process and the heat for the 2nd Process using the tables for unit mass of air. c) Calculate the work for the 1st Process and the heat for the 2nd Process per unit kg of air using the specific heat at 300 K.
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Transcript

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00:01 To solve this question, we have mass equals to 28 .97 kilojoules.
00:06 For calvin moll, we have neuveli equals to r bar p1 divided by small p1 into capital f, putting values 8314 into 300 divided by 10 raised to the power 5 into 28 .97.
00:21 V equal to 0 .861, meter cube per kilo grams.
00:26 So again further, we have when p1 will be even, x to the power 1 .2 is not equal to p2 v2 2, 2, 0 .7.
00:36 We have 1 into 0 .861 into 2, 0 .176 into v2, 1 .27.
00:44 We have lead to 0 .2 .0 meters cube per kilogram.
00:49 We have t2 value...
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