00:02
So, in this question, the given data is the value of q1 is equals to 1 .56 into 10 to the power minus 6 coulomb.
00:17
The value of q2 is equals to minus 2 .46 into 10 to the power minus 6 coulomb and the value of q3 is equals to 3 .03 into 10 to the power minus 6 coulomb and here k is given as 9 into 10 to the power 9 newton meter square per coulomb square.
00:46
Now let us draw the diagram where this is suppose represented by q2 and this is q3 and similarly this is represented by q1.
01:01
The value of q1 here is 1 .56 micro coulomb.
01:09
The value of q2 is minus 2 .46 micro coulomb and the value of q3 is 3 .03 micro coulomb and the distance from q1 to q2 is given as 0 .246 meter and the distance from q2 to q3 is given as 0 .147 meter.
01:47
Now to solve this question, we have to apply the concept of coulomb's law which states that the value for f12 is equals to kq1q2 divided by r2 square.
02:19
Now putting down the individual values i .e.
02:22
The value of k here is 9 into 10 to the power 9 into the value of q1 i .e.
02:29
1 .56 into 10 to the power minus 6 into the value of q2 i .e.
02:36
2 .46 into 10 to the power minus 6 divided by the value of r2 i .e.
02:44
0 .246 whole square.
02:47
Upon solving this, we get the value of f12 equals to 0 .5707 newton...