00:01
Hi everyone, in this question, the information given is mass of c3h8 is given to be 2 .38 grams.
00:09
Molar mass of c3h8 is also given to be 44 .11 grams per more.
00:15
A reaction is given, that is combustion of c3h8, c3h8 plus 5 times of oxygen on combustion gives thrice of carbon dioxide plus 4 moles of water.
00:28
What we have to find is the mass of o2 required for the complete combustion of c3h8.
00:38
In the solution first, we will write down the equation once again, c3h8 plus 5o2 upon combustion gives 3 co2 plus 4h2o.
00:53
Given mass of c3h8 is 2 .38.
01:03
Molar mass of c3ha is 44 .11.
01:09
We know that number of moles is equal to given mass divided by the molar mass.
01:23
Therefore, number of moles will be 2 .38 divided by 44 .11, that is equal to 0 .301, that is equal to 0 .3 .8, that is equal to 0 .3 .1, that is equal to 0.
01:39
0 .053...