00:01
In this question, let's first write down two equations first for the frequency.
00:06
Frequency of a simple harmonic oscillator, we can write f which is equals to 1 divided by 2 pi under root of k divided by m.
00:19
This is first equation and second we can write the time period, time period, that is t which is equals to 1 divided by f.
00:30
So it becomes 2 pi under root of m divided by k.
00:36
So this is our second equation.
00:39
The whole question is on these two equations.
00:44
So let's start with the first part.
00:47
In the first, if we increases the mass to the three times of the initial mass, then as we can write down, the time period t is proportional to under root of then it becomes t -dash which is equal to under root 3 multiplied by t so from this we can see that the answer of the first question is true true the given statement is true then next if we double the spring constant then k -dash which is equals to 2k then we can write the t which is proportional to 1 divided by inversely under root of k...