00:01
So for your questions, you actually have submitted too many in one problem, but i'd be happy to help you with this one proof.
00:08
And then you can resubmit the question and ask for just a particular portion of the questions.
00:15
Maybe you know how to do some and not the others.
00:18
And so let's do this proof.
00:22
So we're going to use the double angle identity for sign.
00:24
So that is 2 .sign x, cosine x plus sine x.
00:32
And in the denominator, we're going to use a double angle.
00:34
Angle identity for cosine.
00:36
We're going to use the two cosine squared of x minus one plus cosine x plus one equals that tangent.
00:47
Now we're going to factor in the numerator.
00:49
We're going to pull out that common factor of sine of x.
00:57
And in the denominator, we can see that these ones cancel, and we're going to factor out the cosine of x.
01:11
And now we can reduce this down and it becomes sine x over cosine of x.
01:18
And this becomes tangent of x by the tangent identity and let's see let's see we look at another question and see if i can do something quickly for you you have given sign of theta is equal to one -third you want to find i'll help you with that one so sign of theta is equal to one -third we know that tangent of theta is negative and we want to find cosine of theta and tangent of 2 theta.
02:06
Cosine of theta, and we want to find tangent of 2 theta.
02:13
So we know that sign is positive in the first and second quadrant, and tangent is negative in the second and third...