Question

Question 4 (8 Marks): The intensity $I$ of a beam of y-rays is related to the thickness $x$ of the absorber through which it has passed by the equation: $I = I_0 exp(-\mu x)$ where $I_0$ is the incident intensity and $\mu$ the linear absorption coefficient. The following values of $I$ were obtained for various thickness $x$ of steel. $x$ (mm) $I$ (?A) 5 5.05 10 4.50 15 3.65 20 3.20 25 2.6 (a) Manipulate the equation above to give the equation of a straight line and explain how you would find $\mu$ and $x_{1/2}$, the half-value layer, from this graph. (Note that there is no need to plot a graph here). [4] (b) Plot a graph of $I$ versus $x$, and from the graph determine the half-value layer $x_{1/2}$. [4]

          Question 4 (8 Marks):
The intensity $I$ of a beam of y-rays is related to the thickness $x$ of the absorber through which
it has passed by the equation:
$I = I_0 exp(-\mu x)$
where $I_0$ is the incident intensity and $\mu$ the linear absorption coefficient. The following
values of $I$ were obtained for various thickness $x$ of steel.
$x$ (mm)      $I$ (?A)
5             5.05
10            4.50
15            3.65
20            3.20
25            2.6
(a) Manipulate the equation above to give the equation of a straight line and explain how you
would find $\mu$ and $x_{1/2}$, the half-value layer, from this graph. (Note that there is no need to plot
a graph here).
[4]
(b) Plot a graph of $I$ versus $x$, and from the graph determine the half-value layer $x_{1/2}$.
[4]

Question 4 (8 Marks):
The intensity I of a beam of y-rays is related to the thickness x of the absorber through which
it has passed by the equation:
I = I0 exp(-μ x)
where I0 is the incident intensity and μ the linear absorption coefficient. The following
values of I were obtained for various thickness x of steel.
x (mm) I (?A)
5 5.05
10 4.50
15 3.65
20 3.20
25 2.6
(a) Manipulate the equation above to give the equation of a straight line and explain how you
would find μ and x1/2, the half-value layer, from this graph. (Note that there is no need to plot
a graph here).
[4]
(b) Plot a graph of I versus x, and from the graph determine the half-value layer x1/2.
[4]

Added by Edwin B.

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