Question 4 A random sample of 100 employees in an organization was taken. The confidence interval for the proportion of male employees was formed and found to have a maximum error of 0.12875. The true proportion of male employees is 0.5. Find the confidence level of this interval.
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We are given that $n = 100$, $p = 0.5$, and $E = 0.12875$. The maximum error is given by the formula: $E = z_{\alpha/2} \sqrt{\frac{p(1-p)}{n}}$ where $z_{\alpha/2}$ is the critical z-value corresponding to the confidence level $1 - \alpha$. Show more…
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