00:01
In this problem, we're asked to find the length and width of a rectangle if we know that the perimeter is 58 inches, and we know that the length is 4 inches less than twice the width.
00:16
So we're letting w stand for the width, and the expression 2w minus 4 stands for the length.
00:25
So we're using our formula, p equals 2l plus 2w, where p stands for parameter, l stands for length, and w stands for width.
00:37
So in our rectangle, our l, remember we said it was four inches less than twice the width.
00:45
So we're going to substitute in 58 for p, our perimeter, and for l, and we're using our formula right here.
00:56
We're going to use 2w minus 4, and then of course, w stands for width.
01:04
Using our distributed property, we get 4w minus 8 plus 2w.
01:10
Combining our like terms on the right -hand side, we have 6w minus 8.
01:15
Add 8 to both sides...