00:02
In this question, solution here is for the a part y of n is equals to x of n minus 1 multiply by x of n plus 1.
00:13
So y of 2 is equals to x of 1 multiply by x of 3.
00:20
This implies y of 2 is equals to x of 1 multiply by x of 3.
00:29
So we have y of n is equals to x1 n multiply by x2 of n.
00:41
This is non -linear.
00:44
Now this implies y of n is equals to x of n minus 1 multiply by x of n plus 1.
00:55
This is bt bo stable.
01:00
This is the answer to first part.
01:02
Now for the second part, y of n is equals to nx multiply by 2n plus 1.
01:11
So this is here.
01:12
Y of 1 is equals to x of 3.
01:17
This is y of minus 2 is equals to minus 2 x of minus 3.
01:26
Now here y of 2 is equals to 2x of 5.
01:36
Now this is y of n is equals to nx multiply by 2n plus 1.
01:42
So y of n is equals to nx multiply by 2n plus 1...