00:01
Hello students, let's do this question.
00:02
In this question, sample size n equal to 55, then sample mean xxx equal to 26 .9, sample standard division, sigma equal to 18 .5, and here the value of mu not equal to half an hour, that is, 30 divided by 60, equal to 0 .5.
00:21
So here, the null hypothesis becomes h0 such that mu equal to 0 .5 against the alternative hypothesis achievement said that mu is less than 0 .5 and here the level of significance alpha equal to 0 .05 is given so we know that the formula for the statistic t equal to xx minus mu not divided by sigma upon square root of n now put the values then again the statistic t equal to 26 .9 minus 0 .5 divided by 18 .5 upon square root of 55 equal to 26 .4 divided by 2 .4945 equal to 10 .583 .2 and the corresponding p value equal to 0 .0000001.
01:16
Now next, the sample of n equal to 34 observations are given.
01:21
Then sample mean x -pa equal to 17 .9, standard division sigma equal to 4 .6 and the value of mu not equal to 20.
01:30
And here, the nile hypothesis is h -0 such that mu equal to 20 against the alternative hypothesis h1 such that mu is less than 20...