Consider the 5 molecules/ions: XeF4, IF3O, BrF2O-, IFO2, and ClO3-. All 5 molecules/ions have O and F as terminal atoms only. Draw the Lewis structure where the formal charge is minimized for each molecule and use them to answer the following question: What is the electron geometry of each molecule/ion? 1. Linear 2. Bent 3. Tetrahedral 4. Trigonal pyramidal 5. Trigonal bipyramidal 6. Seesaw 7. T-shaped 8. Octahedral 9. Square pyramidal 10. Square planar XeF4 ClO3- IF3O BrF2O- IFO2
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Draw the Lewis structures for each molecule/ion: XeF4: Xe is the central atom with 8 valence electrons, and each F atom has 7 valence electrons. So, there are a total of 8 + 4(7) = 36 valence electrons. The Lewis structure is: F | Xe - F - F Show more…
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