Question 4 In many devices involved in energy industries, a fluid (liquidor gas) flows through a pipe. If the cross-sectional area ofa pipe is 2.0 m², and the fluid in it has a speed of 1.5 m/s, (a) What is the volume flow rate in m³/s? (i.e.,what volume of fluid pass through any cross-section of the pipe every second?) (b) What mass of fluid passes through any cross-section of thepipe every second, if the fluid has a density of 1.0×10³ kg/m³? Question 5 Use the Bernoulli equation to calculate the pressure drop required to force a water flow that is originally moving at 20 ft/s in a 2 inch diameter pipe through a constriction into a 1 inch diameter pipe while simultaneously dropping 3 ft in elevation. Question 6 Find Buoyant force Using Archimedes principle replaced value 500 cm³ the density of liquid = 1.3 g/cm³, what is the mass? Question 7 Given that a source and sink are in a uniform field of U = 5 m/s, and the source and sink are located at (0, -2) and (0, 2) respectively. The source has a strength of 5 m²/s and the sink has a strength of -40m²/s. (a) Find the magnitude of the velocity at a point on the x-axis at (-4,0) (b) Find the direction of the velocity at the point (-4,0) (c) If the uniform flow is removed, and the sink is now replaced with a source of 40 m²/s, determine the location of the stagnation point in the flow field
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Given that the cross-sectional area \(A = 2 \, m^2\) and fluid velocity \(v = 1.5 \, m/s\), we can calculate the volume flow rate as: \[Q = 2 \times 1.5 = 3 \, m^3/s\] Show more…
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