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Question 4 (7 marks) Consider the toss of a coin. The set of possible outcomes is O = \{H, T\}. There is a probability measure P that describes the likelihood of H and T. Suppose that the lottery X pays 10 dollars if H is up, that $E_P(X) = 6$ and that $Var_P(X) = 4$. Determine the amount X(T) of dollars that X pays if T is up as well as the probabil- ity P(H) of heads and the probability P(T) of tails. Show your calculations.

          Question 4 (7 marks)
Consider the toss of a coin. The set of possible outcomes is O = \{H, T\}. There is a
probability measure P that describes the likelihood of H and T. Suppose that the lottery
X pays 10 dollars if H is up, that $E_P(X) = 6$ and that $Var_P(X) = 4$.
Determine the amount X(T) of dollars that X pays if T is up as well as the probabil-
ity P(H) of heads and the probability P(T) of tails. Show your calculations.
        
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Question 4 (7 marks)
Consider the toss of a coin. The set of possible outcomes is O = {H, T}. There is a
probability measure P that describes the likelihood of H and T. Suppose that the lottery
X pays 10 dollars if H is up, that EP(X) = 6 and that VarP(X) = 4.
Determine the amount X(T) of dollars that X pays if T is up as well as the probabil-
ity P(H) of heads and the probability P(T) of tails. Show your calculations.

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Principles of Economics
Principles of Economics
Gregory Mankiw 8th Edition
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Consider the toss of a coin. The set of possible outcomes is O = {H, T}. There is a probability measure P that describes the likelihood of H and T. Suppose that the lottery X pays 10 dollars if H is up, that E(pX) = 6, and that Var(pX) = 4. Determine the amount X(T) of dollars that X pays if T is up, as well as the probability P(H) of heads and the probability P(T) of tails. Show your calculations.
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Transcript

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00:02 So in item 1, we are assuming that the coin is fair.
00:05 And we want to compute what is the probability that you're going to get four hats.
00:10 So let's say the x is the number of hats that we can get out of nine times that we cause a toss a coin.
00:20 So this means here that because we are counted the number of heads out of like a total number of tosses here.
00:29 This means that x has a binomial distribution with, in this case, two parameters.
00:38 The number of tosses, nine, and the probability of getting one had, so 0 .5.
00:44 So with this information, we can use the formula given by the binomid distribution that says that the probability of x being equals to a little x is equal to the combination of the total number of tosses, and we put the number of tosses that we got had, then the probability of getting had at power of the number of heads that we got, and the probability of not getting had, which is one minus this number, but it's the same, for the rest of the tosses here.
01:19 So when we say that we want four, this means that i should put where we have little x4, so we have this...
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