00:01
Okay, so for the transmission of the large file of size f bytes over a root considering, excuse me, consisting of five links, the total delay consists of dtrans, which is the transmission delay, and dprop, which is the propagation delay, and this is for question a.
00:23
So as for transmission delay, so this is the time that it takes to push the entire file onto the link.
00:35
And since each byte has 8 bits, the file size in bits is f times 8.
00:42
And the transmission delay for one link is f times 8 over r seconds.
00:51
And for 5 links this delay is multiplied by 5 and this is for d -trans and for the prop this is the time that it takes for a bit to propagate from the sender to the receiver across a link now given the propagation delay per link is t prop the total propagation delay across five links is 5 times t prop now the the total run trip time, rtt, for the message and its acknowledgement can be calculated as the 2 times the trans plus the prop.
01:37
And the delay from the start of the transmission at the sender to the receipt of the acknowledgement at the sender for one large message is given by total delay equals 80 times f over r plus 10 times tprop...