This is a permutation problem.
We have a set of $n = 11$ numbers (from 1 to 11).
We need to choose $k = 4$ different numbers.
Since the order matters, we use the permutation formula:
$$P(n, k) = \frac{n!}{(n-k)!}$$
In this case, $n = 11$ and $k = 4$.
Step
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