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Question 5 (1 point) Indicate the correct set of reactions from the choices below that would accomplish the following synthesis MOST efficiently (Hint: what is the MAJOR product of each step). target: OH OCH3 starting material: Br 1. DBU, 2. PhCO3H, 3. NaOCH3 then HCl 1. NaOCH3, low temp., 2. H2O2, 3. DMS 1. KOtBu, 2. OsO4, H2O2, H2O, 3. CH3OH 1. DBN, 2. MCPBA, 3. HCl (cat.), HOCH3 1. KOtBu, 2. Br2, CH3OH, H2O

          Question 5 (1 point)
Indicate the correct set of reactions from the choices below that would accomplish the following synthesis MOST efficiently (Hint: what is the MAJOR product of each step).
target: OH OCH3
starting material: Br
1. DBU, 2. PhCO3H, 3. NaOCH3 then HCl
1. NaOCH3, low temp., 2. H2O2, 3. DMS
1. KOtBu, 2. OsO4, H2O2, H2O, 3. CH3OH
1. DBN, 2. MCPBA, 3. HCl (cat.), HOCH3
1. KOtBu, 2. Br2, CH3OH, H2O
        
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Question 5 (1 point)
Indicate the correct set of reactions from the choices below that would accomplish the following synthesis MOST efficiently (Hint: what is the MAJOR product of each step).
target: OH OCH3
starting material: Br
1. DBU, 2. PhCO3H, 3. NaOCH3 then HCl
1. NaOCH3, low temp., 2. H2O2, 3. DMS
1. KOtBu, 2. OsO4, H2O2, H2O, 3. CH3OH
1. DBN, 2. MCPBA, 3. HCl (cat.), HOCH3
1. KOtBu, 2. Br2, CH3OH, H2O

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Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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Indicate the correct set of reactions from the choices below that would accomplish the following synthesis MOST efficiently (Hint: what is the MAJOR product of each step): 1. DBU, 2. PhCO3H, 3. NaOCH3 then HCl 1. NaOCH3, low temp., 2. H2O2, 3. DMS 1. KOtBu, 2. OsO4, H2O2, H2O, 3. CH3OH 1. DBN, 2. MCPBA, 3. HCl (cat.), HOCH3 1. KOtBu, 2. Br2, CH3OH, H2O
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Transcript

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00:01 Hi, in this question we are given with this target molecule and we are given with the starting material.
00:06 We are asked to choose the correct set of reactions to reach up to this target molecule.
00:12 In the first step, starting material react with a base that is d .bu.
00:17 This will abstract this proton as a result of which it will transfer its bond electron to sigma star of carbon br bond as a result br will be released.
00:27 And we will get this cycloalkene.
00:31 Now this will react with ph co3h.
00:36 This is a peroxide and it will cause the epoxidation of this alken as a result of which and we will get a three -membered ring.
00:45 Now it will react with naoch3...
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