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Question 5 1 pts What is the \( \mathrm{pH} \) of \( 2.1 \times 10^{-5} \mathrm{M} \mathrm{NaOH}(\mathrm{aq}) \) at \( 25^{\circ} \mathrm{C} \) ? \( \left(K_{\mathrm{w}}=1.0\right. \) \( \times 10^{-14} \) ) 3.23 9.32 \( -4.68 \) 10.77 4.68

          Question 5
1 pts
What is the \( \mathrm{pH} \) of \( 2.1 \times 10^{-5} \mathrm{M} \mathrm{NaOH}(\mathrm{aq}) \) at \( 25^{\circ} \mathrm{C} \) ? \( \left(K_{\mathrm{w}}=1.0\right. \) \( \times 10^{-14} \) )
3.23
9.32
\( -4.68 \)
10.77
4.68

Question 5
1 pts
What is the pH of 2.1 × 10^-5MNaOH(aq) at 25^∘C ? (Kw=1.0. × 10^-14 )
3.23
9.32
-4.68
10.77
4.68

Added by Chelsea A.

General Chemistry

Darrell Ebbing, Steven D. Gammon 11th Edition

Chapter 15

Instant Answer

Solved by Expert Derrick Danso

Step 1

The question asks for the pH of a 2.1 x 10^-5 M NaOH solution at 25°C. NaOH is a strong base, meaning it dissociates completely in water. The pH scale is used to determine the acidity or basicity of a solution, with values less than 7 indicating acidity, values Show more…

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Question 5 1 pts What is the \( \mathrm{pH} \) of \( 2.1 \times 10^{-5} \mathrm{M} \mathrm{NaOH}(\mathrm{aq}) \) at \( 25^{\circ} \mathrm{C} \) ? \( \left(K_{\mathrm{w}}=1.0\right. \) \( \times 10^{-14} \) ) 3.23 9.32 \( -4.68 \) 10.77 4.68