At an amusement park, a 98.5 kg bumper car moving with a speed of 1.18 m/s bounces elastically off a second 140-kg bumper car that is moving with a speed of 1.02 m/s in the opposite direction. Find the final velocities of the two cars.
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The total momentum before the collision is: p_before = m1*v1 + m2*v2 where m1 and v1 are the mass and velocity of the first car, and m2 and v2 are the mass and velocity of the second car. Plugging in the numbers, we get: p_before = 98.5 kg * 1.18 m/s + 140 kg * Show more…
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