Question 5 A mixture of 100mol containing 60mol% n-pentane and 40% n-heptane is vaporized at 101.32kPa abs pressure until 40mol of vapor and 60mol of liquid in equilibrium with each other are produced. This occurs in a single-stage system and the vapor and the liquid are kept in contact with each other until the vaporization is complete. The relative volatility of n-pentane to n-heptane is 3.0. Calculate the composition of the vapor and the liquid.
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- Total moles of mixture: 100 mol - Composition of mixture: 60 mol% n-pentane, 40 mol% n-heptane - Moles of vapor: 40 mol - Moles of liquid: 60 mol - Relative volatility (\(\alpha\)) of n-pentane to n-heptane: 3.0 Show more…
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A mixture of 100 mol containing 50 mol % n-pentane and 50 mol % n-heptane is distilled under differential conditions at 101.3 kPa until 40 mol is distilled. What is the average composition of the total vapor distilled and the composition of the liquid left? The equilibrium data are as follows, where x and y are mole fractions of n-pentane. x y x y x y 1.000 1.000 0.398 0.836 0.059 0.271 0.867 0.984 0.254 0.701 0 0 0.594 0.925 0.145 0.521
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A mixture of 100 kg mol which contains 60 mol% n-pentane (a) and 40 mol% n-heptane (b) is vaporized at 101.3 kPa pressure. If the vaporization is done in an equilibrium distillation and 40 kg mol are distilled, what is the composition of the vapor distilled and of the liquid left?
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