Question (5) A random variable X has this probability distribution: x 0 1 2 3 4 P(x) ? 1/6 1/4 ? 1/3 1) Given that E(X) = 5/2, find ? and ?. 2) Calculate E(X^2) and V(X). 3) If Y = 9 - 2X, find E(Y) and V(Y).
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We can use the formula for the expected value: E(X) = Σ[x * P(x)] 5 = (2 * 1/6) + (3 * 1/4) + (B * 1/3) Now, we can solve for B: 5 = (1/3) + (3/4) + (B/3) 5 = (4 + 9 + 4B) / 12 60 = 13 + 4B 47 = 4B B = 47/4 Show more…
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