00:01
Hello students, in this question we are given multiple sub parts.
00:05
Now for part a we have to find the resolution of the conversion in volt.
00:12
So resolution is equal to input voltage range divided by 2n.
00:24
Here n is the number of bits that is given as 8 and range is given as 10 to the power v.
00:39
Now putting the values here we get 10 over 2 power 8.
00:45
So after solving this we get 39 .0625 mv.
00:52
Now for p part we have to find the digital representation of an input of 6 volt.
01:00
So representation of 6 volt is now for this using the relation v2 divided by v1 t1.
01:09
Now substituting the values we get 6 divided by 10 into 256.
01:14
This will be gives as 153 .6 that is 154 .10.
01:20
So we can write this will be 100110 base of 2.
01:28
Now for c part next in c part we have to representation of an input of 6 .2 volt.
01:40
So the using the relation 2 is equal to v2 by 2 power v1 t1.
01:47
Now substituting the values we get 6 .2...