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Hi there.
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In this question, we are given an unbalanced equation of c3h8 reacting with oxygen.
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So this is a combustion reaction.
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And complete combustion reactions always produce carbon dioxide and water.
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But we are asked to go ahead and balance this.
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And balancing means we need the same number of each type of atom on both sides of the arrow.
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And we accomplish that by adding coefficients, which are whole numbers we place in front of terms.
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So starting on the left, we see that we have three carbons.
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So that means to the right, we need to add a three in front of co2, because that will give us three carbons.
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Next, let's look at hydrogen.
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On the left, we have eight hydrogen.
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On the right, we see h2.
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Whatever coefficient we put in front of h2o, we have to multiply times that two.
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So that means i need a four there, because four times two will give me eight hydrogen...