Question 5 A particle with negative charge q and mass m = 2.58 × 10$^{-15}$ kg is $\vec{v}$ = (1.05 × 10$^6$) m/s (-3$\hat{i}$ + 4$\hat{j}$ + 12$\hat{k}$) and the force $\vec{F}$ on the particle has a magnitude of 2.45 N. (a) Determine the charge q. (b) Determine the acceleration $\vec{a}$ of the particle.
Added by Catalina S.
Close
Step 1
0510 m/s (-3i + 4j + 12k) and the magnitude of the force F = 2.45 N. Show more…
Show all steps
Your feedback will help us improve your experience
Ivan Kochetkov and 80 other Physics 103 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A particle with negative charge q and mass m = 2.58 x 10^-15 kg is traveling through a region containing a uniform magnetic field B = -(0.12 T)k. At a particular instant of time, the velocity of the particle is v = (1.05 x 10^6 m/s)(-3i + 4j + 12k), and the force F on the particle has a magnitude of 2.45 N. a) Determine the charge q. b) Determine the acceleration a of the particle.
Ivan K.
A positively charged particle Q1 = 25 nC is held fixed at the origin. A negatively charged particle Q2 = -36 nC of mass m = 3.5 μg is located at a distance d = 45 cm along the positive x-axis from the positively charged particle. (a) What is the magnitude of the electric force in newtons that acts on the charge Q2? (c) What is the magnitude of the acceleration, a, in m/s2, experienced by charge Q2?
Timothy J.
If a particle with a charge of 1 C enters a magnetic field with a velocity of V = 3i + 5j + 2k m/s and B = 2j + 3k T, find the direction and magnitude of the magnetic force acting on the charge.
Sahil K.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD