Question 6 (1 point) Consider point 1 which is \( y=57.0 \mathrm{~cm} \) above \( \mathrm{a} Q=-2.62 \mu \mathrm{C} \) point charge, and point 2 which is \( x=71.0 \mathrm{~cm} \) left of the charge (see figure). Determine \( \Delta V=V_{2}-V_{1} \) (in \( \mathrm{V} \) ). \( \bullet 1 \) \( y \) \( 2 \bullet \) \( x \) \( Q \) Your Answer: \( \square \) Answer
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62 \mu \mathrm{C} = -2.62 \times 10^{-6} \mathrm{C} \) - Distance from the charge to point 1, \( r_1 = 57.0 \mathrm{~cm} = 0.57 \mathrm{~m} \) - Distance from the charge to point 2, \( r_2 = 71.0 \mathrm{~cm} = 0.71 \mathrm{~m} \) Show more…
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