The driving voltage source of a series RLC circuit is ?rms = 266 volts. The other numbers are: • R = 1.1 ? • L = 0.038 H • C = 6 ?F • ? = 1/?LC Calculate the average inductor energy in the circuit, in Joules.
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Given: R = 110 Ω L = 0.038 H C = 6 pF ω = 1/√(L*C) Total impedance, Z = R + j(ωL - 1/(ωC)) Substitute the values: Z = 110 + j(1/√(0.038*6) * 0.038 - 1/(1/√(0.038*6)*6)) Z = 110 + j(1/√(0.228) * 0.038 - 1/(1/√(0.228)*6)) Z = 110 + j(0.038/0.478 - 1/(0.478*6)) Z = Show more…
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