Question 7 Given \( h(x)=2(x+1)^{2}-2 \), determine the following: a) The vertex: \( (-1,-2) \) b) The \( x \)-intercept(s): \( \square \) c) \( y \)-intercept: \( \square \) d) Domain: \( \square \) e) Range: \( \square \)
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The function is given in vertex form: \( h(x) = 2(x+1)^2 - 2 \). The vertex form of a quadratic function is \( a(x-h)^2 + k \), where \((h, k)\) is the vertex. Here, the vertex is \((-1, -2)\). Show more…
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