Water with density 1000 kg/m³ moves with speed 6.0 m/s in a horizontal pipe with a diameter of 4.0 cm. The pipe then narrows to a diameter of 1.0 cm. What is the rate of mass of flow through the narrower section of the pipe in kg/s? A 0.0075 kg/s B 0.030 kg/s C 7.5 kg/s D 30 kg/s
Added by Caleb S.
Close
Step 1
The cross-sectional area of a pipe can be calculated using the formula A = πr^2, where A is the cross-sectional area and r is the radius of the pipe. For the initial section with a diameter of 4.0 cm, the radius is half of the diameter, so r = 2.0 cm = 0.02 Show more…
Show all steps
Your feedback will help us improve your experience
Hubert Agamasu and 91 other Physics 103 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Suman K.
3. One end of a cylindrical pipe has a radius of 1.5 cm. Water (density = 1.0 × 10^3 kg/m^3) streams steadily out at 7.0 m/s. The rate at which mass is leaving the pipe is: (a) 2.5 kg/s (b) 4.9 kg/s (c) 7.0 kg/s (d) 48 kg/s (e) 7.0 × 10^3 kg/s
Arjun C.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD