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Question 8 0.9 pts The complex ion, \( \left[\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+} \), has a maximum absorption near \( 580 \mathrm{~nm} \). Calculate the crystal field splitting energy (in \( \mathrm{kJ} / \mathrm{mol} \) ) for this ion. \( 206 \mathrm{~kJ} / \mathrm{mol} \) \( 114 \mathrm{~kJ} / \mathrm{mol} \) \( 292 \mathrm{~kJ} / \mathrm{mol} \) \( 343 \mathrm{~kJ} / \mathrm{mol} \) \( 485 \mathrm{~kJ} / \mathrm{mol} \)

          Question 8
0.9 pts
The complex ion, \( \left[\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+} \), has a maximum absorption near \( 580 \mathrm{~nm} \). Calculate the crystal field splitting energy (in \( \mathrm{kJ} / \mathrm{mol} \) ) for this ion.
\( 206 \mathrm{~kJ} / \mathrm{mol} \)
\( 114 \mathrm{~kJ} / \mathrm{mol} \)
\( 292 \mathrm{~kJ} / \mathrm{mol} \)
\( 343 \mathrm{~kJ} / \mathrm{mol} \)
\( 485 \mathrm{~kJ} / \mathrm{mol} \)

Question 8
0.9 pts
The complex ion, [Ni(NH3)6]^2+, has a maximum absorption near 580 nm. Calculate the crystal field splitting energy (in kJ / mol ) for this ion.
206 kJ / mol
114 kJ / mol
292 kJ / mol
343 kJ / mol
485 kJ / mol

Added by Gabriel W.

Chemistry A Molecular Approach

Nivaldo J. Tro 4th Edition

Chapter 25

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Solved by Expert Penny Riley

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The crystal field splitting energy (\( \Delta \)) is the energy difference between the d orbitals that are split into two levels in a crystal field, such as in a transition metal complex. This energy difference is responsible for the color of the complex due to Show more…

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Question 8 0.9 pts The complex ion, \( \left[\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+} \), has a maximum absorption near \( 580 \mathrm{~nm} \). Calculate the crystal field splitting energy (in \( \mathrm{kJ} / \mathrm{mol} \) ) for this ion. \( 206 \mathrm{~kJ} / \mathrm{mol} \) \( 114 \mathrm{~kJ} / \mathrm{mol} \) \( 292 \mathrm{~kJ} / \mathrm{mol} \) \( 343 \mathrm{~kJ} / \mathrm{mol} \) \( 485 \mathrm{~kJ} / \mathrm{mol} \)