Question 8 (1 point) Saved How much force is needed to overcome the frictional force of a 1000 kg car with wheels of radius 23 cm and the coefficient of rolling friction (d) = 1 cm? Your Answer: N Answer units
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A car weighs $1800 \mathrm{~kg}$. The distance between its $\mathrm{ft}_{\text {aly }}$ and back axles is $1.8 \mathrm{~m}$. Its centre of gravity is behind the front axle. The force exerted by the $\mathrm{l}_{\mathrm{m}}$ ground on each front wheel and each back wheel ground on (Take $g=10 \mathrm{~ms}^{-2}$ ) (a) $4000 \mathrm{~N}$ on each front wheel, $5000 \mathrm{~N}$ on $\mathrm{e}_{2 \mathrm{Ch}}$ back wheel (b) $5000 \mathrm{~N}$ on each front wheel, $4000 \mathrm{~N}$ an each back wheel (c) $4500 \mathrm{~N}$ on each front wheel, $4500 \mathrm{~N}$ on each back wheel (d) $3000 \mathrm{~N}$ on each front wheel, $6000 \mathrm{~N}$ on each back wheel
A car of mass $2000 \mathrm{~kg}$ is moving with a speed of $10 \mathrm{~ms}^{-1}$ on a circular path of radius $20 \mathrm{~m}$ on a level road. What must be the frictional force between the car and the road so that the car does not slip? (a) $10^{4} \mathrm{~N}$ (b) $10^{3} \mathrm{~N}$ (c) $10^{5} \mathrm{~N}$ (d) $10^{2} \mathrm{~N}$
Circular Motion
Round 1
A 100 kg car is moving with a maximum velocity of 9 m/s across a circular track of radius 30 m. The maximum force of friction between the road and the car is (a) 1000 N (b) 706 N (c) 270 N (d) 200 N
Kamlesh G.
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