00:01
We'd like to determine the acceleration of the object.
00:03
So we can use our equation of motion.
00:06
S is equal to u -t plus one -half a -t squared.
00:10
Now we're told our distance is 1 .05 meters equal to this goes to zero.
00:16
So we have 1 -half times a times 4 .70 squared.
00:21
So we can go ahead and solve this for our acceleration.
00:25
So our acceleration is going to be 2 times 1 .0.
00:30
Divided by 4 .70 squared, which is 0 .095 meters per second squared.
00:44
Now for part b, we would like to find the tension in the string.
00:50
So to find the tension in the string, we'd want to consider our motion for mass one, or for mass one.
00:58
Mass one just has the weight force and our tension force.
01:03
So we can look at this motion here.
01:06
We have tension minus mass one times gravity equal to mass one times acceleration.
01:12
So we can plug in tension minus mass one, which is four kilograms.
01:17
So four times 9 .8 equal to 4 times 0 .095.
01:23
And so we can solve for our tension.
01:25
So our tension is 4 times 0 .095 plus 4 times 9 .8, which is 39 .5 newtons for our tension...