A mass of 1.76 kg is initially at rest upon a horizontal surface. An applied force of 19.5 N i then acts on the mass. If the coefficient of kinetic friction regarding the system is 0.605, what is the magnitude of the object's acceleration? A 1.77 kg mass is sliding across a horizontal surface an initial velocity of 11.5 m/s i. If the object then comes to a stop over a time of 2 seconds, what must the coefficient of kinetic be? Assume that only friction, the normal force, and the force due to gravity are acting on the mass. Enter a number rounded to 3 decimal places.
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1. A block of mass 113 g slides on a horizontal surface a distance of 2.0 m before it stops. If the initial speed of the block was 4.5 m/s, what is the coefficient of kinetic friction between the block and the surface? 2. A block of mass M = 5.0 kg is placed on a horizontal table. The coefficient of kinetic friction between the block and the table is 0.21. The block is connected to a mass m = 4.0 kg with a string passed over a pulley. Mass m is moving vertically. Calculate the acceleration of this system, in m/s2.
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A 1.8 -kg block slides on a horizontal surface with a speed of $v=0.80 \mathrm{m} / \mathrm{s}$ and an acceleration of magnitude $a=2.8 \mathrm{m} / \mathrm{s}^{2},$ as shown in FIGURE $6-30$ . (a) What is the coefficient of kinetic friction between the block and the surface? (b) When the speed of the block slows to 0.40 $\mathrm{m} / \mathrm{s}$ , is the magnitude of the acceleration greater than. less than, or equal to 2.8 $\mathrm{m} / \mathrm{s}^{2}$ ? Explain.
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