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Question 8: Angular velocity of a rolling rigid body A circular rigid body is rolling without slipping on a flat surface in 2D as shown. Point Q has: $\vec{r}_{CQ} = -12\hat{i} + 5\hat{j}$ m $\vec{v}_{Q} = -72\hat{i} - 48\hat{j}$ m/s. Matlab Mathematica Python R SymPy from sympy import * rCQ = Matrix([-12, 5, 0]) vQ = Matrix([-72, -48, 0]) copy this text What is the angular velocity $\vec{\omega}$? $\vec{\omega} = $ ____ $k$ rad/s

          Question 8: Angular velocity of a rolling rigid body
A circular rigid body is rolling without slipping on a flat surface in 2D as shown.
Point Q has:
$\vec{r}_{CQ} = -12\hat{i} + 5\hat{j}$ m
$\vec{v}_{Q} = -72\hat{i} - 48\hat{j}$ m/s.
Matlab Mathematica Python R SymPy
from sympy import *
rCQ = Matrix([-12,  5,  0])
vQ = Matrix([-72, -48,  0])
copy this text
What is the angular velocity $\vec{\omega}$?
$\vec{\omega} = $ ____ $k$ rad/s

Question 8: Angular velocity of a rolling rigid body
A circular rigid body is rolling without slipping on a flat surface in 2D as shown.
Point Q has:
r⃗CQ = -12î + 5ĵ m
v⃗Q = -72î - 48ĵ m/s.
Matlab Mathematica Python R SymPy
from sympy import *
rCQ = Matrix([-12, 5, 0])
vQ = Matrix([-72, -48, 0])
copy this text
What is the angular velocity ω⃗?
ω⃗ = k rad/s

Added by Kevin M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Sam Stansfield

Step 1

The linear velocity is given by the cross product of the angular velocity and the position vector from the axis of rotation to the point. v = ω × r where v is the linear velocity, ω is the angular velocity, and r is the position vector. In this case, the Show more…

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Question 8: Angular velocity of a rolling rigid body Proctor A circular rigid body is rolling without slipping on a flat surface in 2D as shown: Point Q has: TcQ = (-121, 5) m Uq = (721, 48) m/s. Matlab Mathematica Python SymPy from sympy import rcQ = Matrix([-12, Matrix([-72, 48, 0]) 0]) copy this text What is the angular velocity Ï‰? krad/s