Question 8 How many oxygen atoms are there in $5.64 \times 10^{-9}$ g of $Ca_3(PO_4)_2$? A. $1.09 \times 10^{13}$ B. $8.76 \times 10^{13}$ C. $4.38 \times 10^{13}$ D. $2.72 \times 10^{16}$ E. $2.72 \times 10^{13}$
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The molar mass of Ca is 40.08 g/mol. The molar mass of P is 30.97 g/mol. The molar mass of O is 16.00 g/mol. So, the molar mass of Ca3(PO4)2 is: 3(40.08 g/mol) + 2(30.97 g/mol) + 8(16.00 g/mol) = 310.18 g/mol. Show more…
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