00:01
In this question we need to find out the specific gravity of mercury and the liquid used in thermometer if it has a density of 13 .6 gram per millimeter.
00:24
So this is a density and we need to find out the specific gravity of mercury here.
00:29
So we can say that the specific gravity which is equal to, actually it is a ratio of density of the substance to the density of water.
00:40
So here we are concerning with mercury.
00:43
Therefore, we can say that specific gravity of mercury which is equal to the density of mercury divided by density of water.
00:53
Density of mercury, which is already, it is already given in 13 .6 gram per milliliter.
00:59
And density of water is 0 .998 gram.
01:04
Gram per milliliter.
01:06
So let's substitute these values in this formula.
01:10
Therefore we can find out the specific gravity and density of mercury is 13 .6 gram per millimeter and for density of water is 0 .998 gram per millimeter and this is equal to 13 .61.
01:35
So this is the answer to this question...