Question

Two cylindrical rods, one stainless steel and the other annealed copper, are joined end to end. Each rod is 1.00 m long and 1.50 cm in diameter. The combination is subjected to a tensile force with magnitude 4000 N. For each rod, what is the elongation? Ysteel = 2.0 x 10^11 Pa, Ycopper = 1.1 x 10^11 Pa For steel, 1.1 x 10^-4 ; for copper, 2.1 x 10^-4 For steel, 8.3 x 10^-5 ; for copper, 1.6 x 10^-4 For steel, 2.1 x 10^-4 ; for copper, 1.1 x 10^-4 For steel, 1.6 x 10^-4 ; for copper, 8.3 x 10^-5

          Two cylindrical rods, one stainless steel and the other annealed copper, are joined end to end. Each rod is 1.00 m long and 1.50 cm in diameter. The combination is subjected to a tensile force with magnitude 4000 N. For each rod, what is the elongation? Ysteel = 2.0 x 10^11 Pa, Ycopper = 1.1 x 10^11 Pa

For steel, 1.1 x 10^-4 ; for copper, 2.1 x 10^-4
For steel, 8.3 x 10^-5 ; for copper, 1.6 x 10^-4
For steel, 2.1 x 10^-4 ; for copper, 1.1 x 10^-4
For steel, 1.6 x 10^-4 ; for copper, 8.3 x 10^-5

Two cylindrical rods, one stainless steel and the other annealed copper, are joined end to end. Each rod is 1.00 m long and 1.50 cm in diameter. The combination is subjected to a tensile force with magnitude 4000 N. For each rod, what is the elongation? Ysteel = 2.0 x 10^11 Pa, Ycopper = 1.1 x 10^11 Pa

For steel, 1.1 x 10^-4 ; for copper, 2.1 x 10^-4
For steel, 8.3 x 10^-5 ; for copper, 1.6 x 10^-4
For steel, 2.1 x 10^-4 ; for copper, 1.1 x 10^-4
For steel, 1.6 x 10^-4 ; for copper, 8.3 x 10^-5

Added by Sara C.

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