Question 9 (2 points) ? Saved Suppose a research firm conducted a survey to determine the mean amount steady smokers spend on cigarettes during a week. A sample of 100 steady smokers revealed that the sample mean is $20 and the sample standard deviation is $5. What is the probability that a sample of 100 steady smokers spend between $19 and $21? 1.0000 0.9544 0.0228 0.4772
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In this case, the sample standard deviation is $5 and the sample size is 100, so the SEM is $5 / √100 = $5 / 10 = $0.5. Show more…
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