Question

A sample of pure sodium carbonate Na2CO3 ( M.mass 106 g/mol) ,weighing 0.3542g is dissolved in water and titrated with a solution of HCl .A volume of 30.23mL is required to reach the Methyl-Orange end point .The molarity of the acid solution is : (2HCl+Na2CO3?2NaCl +H2O+CO2) Select one: a. 0.2121 b. 0.2211 c. 0.1122 d. 0.1212 e. 0.02211

          A sample of pure sodium carbonate Na2CO3 ( M.mass 106 g/mol) ,weighing 0.3542g is dissolved in water and titrated with a solution of HCl .A volume of 30.23mL is required to reach the Methyl-Orange end point .The molarity of the acid solution is :
(2HCl+Na2CO3?2NaCl +H2O+CO2)
Select one:
a. 0.2121
b. 0.2211
c. 0.1122
d. 0.1212
e. 0.02211

A sample of pure sodium carbonate Na2CO3 ( M.mass 106 g/mol) ,weighing 0.3542g is dissolved in water and titrated with a solution of HCl .A volume of 30.23mL is required to reach the Methyl-Orange end point .The molarity of the acid solution is :
(2HCl+Na2CO3?2NaCl +H2O+CO2)
Select one:
a. 0.2121
b. 0.2211
c. 0.1122
d. 0.1212
e. 0.02211

Added by James G.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Chittaranjan Sahoo

01/24/2022

Step 1

Moles of Na2CO3 = mass (g) / molar mass (g/mol) Moles of Na2CO3 = 0.3542 g / 106 g/mol = 0.00334 mol Show more…

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A sample of pure sodium carbonate Na2CO3 (M.mass 106 g/mol), weighing 0.3542g is dissolved in water and titrated with a solution of HCl .A volume of 30.23mL is required to reach the Methyl-Orange end point .The molarity of the acid solution is : (2HCl+Na2CO3→2NaCl +H2O+CO2) Select one: a. 0.2121 b. 0.2211 c. 0.1122 d. 0.1212 e. 0.02211