Question 9 of 9 (1 point) | Attempt 1 of Unlimited | View question in a popup A normal population has mean $\mu = 33$ and standard deviation $\sigma = 7$. (a) What proportion of the population is between 18 and 29? (b) What is the probability that a randomly chosen value will be between 26 and 36? Round the answers to at least four decimal places. Part: 0/2 Part 1 of 2 The proportion of the population between 18 and 29 is
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For 18: z = (18 - 33) / 7 = -2.14 For 29: z = (29 - 33) / 7 = -0.57 Show more…
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