00:01
Hello students in this question given that ice which is kept is converted to water and the change in temperature is given.
00:13
Mass of the ice is also given.
00:15
First we need to find out the amount of heat energy transferred.
00:19
For that we can use the formula mass into latent heat of fusion of water plus specific heat capacity of water in our ice into delta.
00:32
T.
00:35
Here, delta t can be calculated by using the change in temperature, which is final temperature 15 degrees celsius minus initial temperature of ice minus 10 degrees celsius, which gives 25 degrees celsius.
00:52
As we are taking difference between them, no need to convert them to kelvin.
00:58
Hence now substitute for mass, which is 0 .01 kg.
01:05
It is converted from.
01:06
Gram to kg then latent heat of fusion of water plus specific heat capacity into delta t that is 25.
01:23
From this calculation the amount of heat obtained is 3 ,0885 jowl.
01:31
Now change in entropy can be calculated by using the formula amount of heat energy transferred by average temperature.
01:39
Average temperature is given by initial temperature plus final temperature divided by 2.
01:48
Now convert this to kelvin minus 10 is converted to kelvin 263 plus 15 is converted to 288 divided by 2...