QUESTION 2 BENDING STRESS-GEARS [37] A pinion with 18 teeth...

QUESTION 2 BENDING STRESS-GEARS [37] A pinion with 18 teeth and a pressure angle of 20° drives a gear with 50 teeth. The module is 5 mm, and the face width is 35 mm. The pinion rotates at 1200 r/min, and the system must transfer 10 kW. The power transfer can be considered smooth. The gears are made from Grade 1 steel, and the Brinell hardness of the pinion and the gear are 300 and 200, respectively. Both gears are made to a number 8 AGMA quality standard, and the teeth are crowned. Assume a pinion life of 10^8 cycles. The gears are straddle mounted in a precision enclosed gear unit, and a reliability of 90% is required. 2.2 Calculate the AGMA bending stress for the pinion and gear. (34)

Transcript

00:01 So, here in this quotient we are given a pinion which is having the 18 teeth.

00:07 So, number of teeth is given to us n that is equals to 18 and the pressure angle let's say alpha is given that is equals to 20 degree which cries with 50 teeth.

00:18 The module is given that is equals to 5 millimeter and the face is given that is 35 millimeter.

00:25 So, here what we are considering that wicker gear is a gear which having the minimum value of the beam strength and always designed for the wicker gear.

00:35 So, when pinion and gear both are made up of the sample same material then sigma of b for p is equals to sigma of b for g.

00:43 Now, here we are considering that m1 is equals to m2 that from here is equals to 5 and b1 is equals to b2 that from here is equals to 35 millimeter.

00:55 So, here we are considering about the lavish form factor which is represented by y that is equals to pi which is multiplied by the y where y representing the tooth form factor.

01:05 So, y from here is equals to 0 .154 minus 0 .912 which is divided by z.

01:13 This is for full depth and phi is given that is equals to 20 degree.

01:17 So, the value of y from here is equals to pi multiplied by the 0 .154 minus 0 .912 that is divided by z.

01:26 Now, z is the number of teeth.

01:29 So, zp from here is equals to 18 and zz is equals to 20.

01:34 So, we can say that the value of z of z which is greater than z of p then we can say that the value of y of z from here is greater than y of p.

01:43 So, from here we are considering that ft for the maximum value at p is must be less than ft for the maximum value of g.

01:55 So, from here the power is given that is equals to 2 pi multiplied by the nt which is divided by 60.

02:02 Plugging into the values we have to find out the value of t that from here is equals to 60 multiplied by the 10 multiplied by the 10 raised to the power 3 that is divided by 2 pi which is multiplied by the 1200.

02:14 So, solving the term from here we get the value of t that become equals to 79 .55 newton meter and now we are considering about ft that from here is equals to 2t which is divided by t that is equals to 2t divided by mg...

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